Thread: SAC origin time header change

Hi Reza,

Your problem is the dates and times,

Your original trace begin the record on JAN 01 (001), 1983, 12:06:24.194

and you want setting an origin time on 1982 123 13 37 10 103,

so, only for test, sac write the header O, you can not see the mark because it
is out of the trace time window.

See the O marker in second header.

HTH,

Milton

FILE: ./1983-01-01-1205-51S.rez___019_TBZ___SP_Z_SAC - 1
----------------------------------------------------

NPTS = 14408
B = 0.000000e+00
E = 2.881400e+02
IFTYPE = TIME SERIES FILE
LEVEN = TRUE
DELTA = 2.000000e-02
DEPMIN = -7.530000e+02
DEPMAX = 5.900000e+02
DEPMEN = 4.927818e-03
KZDATE = JAN 01 (001), 1983
KZTIME = 12:06:24.194
KSTNM = TBZ
CMPAZ = 0.000000e+00
CMPINC = 0.000000e+00
STLA = 3.823483e+01
STLO = 4.614983e+01
STEL = 1.550000e+03
LOVROK = TRUE
NVHDR = 6
NORID = 0
NEVID = 0
LPSPOL = FALSE
LCALDA = TRUE
KCMPNM = SP Z
KNETWK =
MAG = 0.000000e+00
SAC> ch O gmt 1982 123 13 37 10 103
SAC> lh


FILE: ./1983-01-01-1205-51S.rez___019_TBZ___SP_Z_SAC - 1
----------------------------------------------------

NPTS = 14408
B = 0.000000e+00
E = 2.881400e+02
IFTYPE = TIME SERIES FILE
LEVEN = TRUE
DELTA = 2.000000e-02
DEPMIN = -7.530000e+02
DEPMAX = 5.900000e+02
DEPMEN = 4.927818e-03
OMARKER = -2.099e+07
KZDATE = JAN 01 (001), 1983
KZTIME = 12:06:24.194
KSTNM = TBZ
CMPAZ = 0.000000e+00
CMPINC = 0.000000e+00
STLA = 3.823483e+01
STLO = 4.614983e+01
STEL = 1.550000e+03
LOVROK = TRUE
NVHDR = 6
NORID = 0
NEVID = 0
LPSPOL = FALSE
LCALDA = TRUE
KCMPNM = SP Z
KNETWK =
MAG = 0.000000e+00


Milton P. Plasencia Linares
mpplasencia<at>gmail.com



On May 26, 2014, at 10:07 AM, Reza Rezaei <re.rezaei<at>gmail.com> wrote:

1982 123 13 37 10 103