Wenkai Song
Hi,
In order to make the B and KZTIME of the three components consistent, I conducted "synchronize" command. The SAC informed: ERROR 0: Resulting error from shift exceeded tolerance (1e-6): 0.0005. Could you tell me what the error is and how can I fix it, please?
The attached files are the original files that yielded errors.
Thank you!
In order to make the B and KZTIME of the three components consistent, I conducted "synchronize" command. The SAC informed: ERROR 0: Resulting error from shift exceeded tolerance (1e-6): 0.0005. Could you tell me what the error is and how can I fix it, please?
The attached files are the original files that yielded errors.
Thank you!
-
Milton Plasencia
2018-08-23 02:50:27Hi,
On Mac osx and SACv.101.6a the command synchronise works.
Here my commands,
SAC> r 1*
17.18.15.BMRxxx_RO.BHZ.sac 17.18.17.BMRxxx_RO.BHE.sac
17.18.21.BMRxxx_RO.BHN.sac
SAC> synchronize begin on
SAC> p1
SAC> qdp off
SAC> p1
SAC> lh
FILE: 17.18.15.BMRxxx_RO.BHZ.sac - 1
--------------------------------
NPTS = 22532
B = 0.000000e+00
E = 1.126550e+03
IFTYPE = TIME SERIES FILE
LEVEN = TRUE
DELTA = 5.000000e-02
IDEP = UNKNOWN
DEPMIN = 8.240000e+02
DEPMAX = 1.750000e+03
DEPMEN = 1.237252e+03
KZDATE = JUL 28 (209), 2018
KZTIME = 17:18:15.770
KSTNM = BMR
CMPAZ = 0.000000e+00
CMPINC = 0.000000e+00
STLA = 4.767280e+01
STLO = 2.349690e+01
STEL = 2.270000e+02
STDP = 0.000000e+00
KEVNM = tmpevent
EVLA = -2.997600e+01
EVLO = -1.774360e+02
EVDP = 3.470000e+01
KHOLE =
DIST = 1.735385e+04
AZ = 3.234513e+02
BAZ = 4.986711e+01
GCARC = 1.560796e+02
LOVROK = TRUE
NVHDR = 6
NORID = 0
NEVID = 0
LPSPOL = FALSE
LCALDA = TRUE
KCMPNM = BHZ
KNETWK = RO
FILE: 17.18.17.BMRxxx_RO.BHE.sac - 2
--------------------------------
NPTS = 22547
B = 0.000000e+00
E = 1.127300e+03
IFTYPE = TIME SERIES FILE
LEVEN = TRUE
DELTA = 5.000000e-02
IDEP = UNKNOWN
DEPMIN = -8.740000e+03
Waiting
DEPMAX = -6.476000e+03
DEPMEN = -7.550445e+03
KZDATE = JUL 28 (209), 2018
KZTIME = 17:18:15.770
KSTNM = BMR
CMPAZ = 9.000000e+01
CMPINC = 9.000000e+01
STLA = 4.767280e+01
STLO = 2.349690e+01
STEL = 2.270000e+02
STDP = 0.000000e+00
KEVNM = tmpevent
EVLA = -2.997600e+01
EVLO = -1.774360e+02
EVDP = 3.470000e+01
KHOLE =
DIST = 1.735385e+04
AZ = 3.234513e+02
BAZ = 4.986711e+01
GCARC = 1.560796e+02
LOVROK = TRUE
NVHDR = 6
NORID = 0
NEVID = 0
LPSPOL = FALSE
LCALDA = TRUE
KCMPNM = BHE
KNETWK = RO
FILE: 17.18.21.BMRxxx_RO.BHN.sac - 3
--------------------------------
NPTS = 22300
B = 0.000000e+00
E = 1.114950e+03
IFTYPE = TIME SERIES FILE
LEVEN = TRUE
DELTA = 5.000000e-02
IDEP = UNKNOWN
DEPMIN = -1.258000e+03
DEPMAX = 4.980000e+02
DEPMEN = -3.162195e+02
KZDATE = JUL 28 (209), 2018
KZTIME = 17:18:15.770
KSTNM = BMR
CMPAZ = 0.000000e+00
CMPINC = 9.000000e+01
STLA = 4.767280e+01
STLO = 2.349690e+01
STEL = 2.270000e+02
STDP = 0.000000e+00
KEVNM = tmpevent
Waiting
EVLA = -2.997600e+01
EVLO = -1.774360e+02
EVDP = 3.470000e+01
KHOLE =
DIST = 1.735385e+04
AZ = 3.234513e+02
BAZ = 4.986711e+01
GCARC = 1.560796e+02
LOVROK = TRUE
NVHDR = 6
NORID = 0
NEVID = 0
LPSPOL = FALSE
LCALDA = TRUE
KCMPNM = BHN
KNETWK = RO
HTH,
Milton
************************************
Milton P. PLASENCIA LINARES
Centro di Ricerche Sismologiche (CRS)
OGS - Istituto Nazionale di Oceanografia e di Geofisica Sperimentale
Borgo Grotta Gigante 42/C
(34010) Sgonico - Trieste - Italia
Tel: +39 040 2140 156 (Udine)
Tel: +39 040 2140 256 (Trieste)
Cel.: +39 331 6481 935
E-mail: mplasencia<at>inogs.it
GPG Key: 22FCFFA8
ASAIN (Antarctic Seismographic Argentinean Italian Network)
**************************************
On Wed, 22 Aug 2018 at 18:07, Wenkai Song <wsvwf<at>mst.edu> wrote:
Hi,
In order to make the B and KZTIME of the three components consistent, I
conducted "synchronize" command. The SAC informed: ERROR 0: Resulting
error from shift exceeded tolerance (1e-6): 0.0005. Could you tell me what
the error is and how can I fix it, please?
The attached files are the original files that yielded errors.
Thank you!
----------------------
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-
George Helffrich
2018-08-23 15:47:22Dear All -
These files have a BEGIN time offset (B header value) that is 5x10**-4 sec, or 0.5 milliseconds.
The ZERO time in a SAC file is only precise to 1 millisecond. The header stores the zero hour, minute, second, and millisecond values as integers.
When you SYNCHRONIZE the files, you’re asking SAC to align the times to a 0.5 millisecond precision, which, for it, is impossible - hence the error message.
If you want to retain the full precision of the BEGIN values in your files (meaning you *really* believe that 0.5 ms time offset), you must do the alignment manually. Here’s how, using the ALLT option of the CHNHDR command. Notice that the 0.5 ms offset is still preserved in the B values for each file:
SAC> r /tmp/*sac
/tmp/17.18.15.BMRxxx_RO.BHZ.sac ...17.18.17.BMRxxx_RO.BHE.sac ...17.18.21.BMRxxx_RO.BHN.sac
SAC> lh files all nzmin nzsec nzmsec
FILE: /tmp/17.18.15.BMRxxx_RO.BHZ.sac
-------------------------------------
nzmin = 18 nzsec = 15
nzmsec = 769
FILE: /tmp/17.18.17.BMRxxx_RO.BHE.sac
-------------------------------------
nzmin = 18 nzsec = 17
nzmsec = 769
FILE: /tmp/17.18.21.BMRxxx_RO.BHN.sac
-------------------------------------
nzmin = 18 nzsec = 21
nzmsec = 269
SAC> ch file 1 allt -5.5
SAC> ch file 2 allt -3.5
SAC> lh files all nzmin nzsec nzmsec
FILE: /tmp/17.18.15.BMRxxx_RO.BHZ.sac
-------------------------------------
nzmin = 18 nzsec = 21
nzmsec = 269
FILE: /tmp/17.18.17.BMRxxx_RO.BHE.sac
-------------------------------------
nzmin = 18 nzsec = 21
nzmsec = 269
FILE: /tmp/17.18.21.BMRxxx_RO.BHN.sac
-------------------------------------
nzmin = 18 nzsec = 21
nzmsec = 269
SAC> lh default
FILE: /tmp/17.18.15.BMRxxx_RO.BHZ.sac
-------------------------------------
NPTS = 22532 B = -5.49950
E = 1121.05 IFTYPE = TIME SERIES FILE
LEVEN = TRUE DELTA = 0.50E-01
IDEP = UNKNOWN DEPMIN = 824.0
DEPMAX = 1750.0 DEPMEN = 1237.25
KZDATE = JUL 28 (209), 2018 KZTIME = 17:18:21.269
...
FILE: /tmp/17.18.17.BMRxxx_RO.BHE.sac
-------------------------------------
NPTS = 22547 B = -3.49950
E = 1123.80 IFTYPE = TIME SERIES FILE
LEVEN = TRUE DELTA = 0.50E-01
IDEP = UNKNOWN DEPMIN = -8740.0
DEPMAX = -6476.0 DEPMEN = -7550.46
KZDATE = JUL 28 (209), 2018 KZTIME = 17:18:21.269
...
FILE: /tmp/17.18.21.BMRxxx_RO.BHN.sac
-------------------------------------
NPTS = 22300 B = 0.50E-03
E = 1114.95 IFTYPE = TIME SERIES FILE
...
On 23 Aug 2018, at 01:06, Wenkai Song <wsvwf<at>mst.edu> wrote:
Hi,
George Helffrich
In order to make the B and KZTIME of the three components consistent, I conducted "synchronize" command. The SAC informed: ERROR 0: Resulting error from shift exceeded tolerance (1e-6): 0.0005. Could you tell me what the error is and how can I fix it, please?
The attached files are the original files that yielded errors.
Thank you!
<17.18.15.BMRxxx_RO.BHZ.sac><17.18.17.BMRxxx_RO.BHE.sac><17.18.21.BMRxxx_RO.BHN.sac>
----------------------
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george<at>elsi.jp
